A negative free-water clearance $\left(-\mathrm{C}_{\mathrm{H}_{2} \mathrm{O}}\right)$ will occur in a person who

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[VII D; Table 5.6]. A person who produces hyperosmotic urine (1,000 $\mathrm{mOsm} / \mathrm{L})$ will have a negative free-water clearance $\left(-\mathrm{C}_{\mathrm{H}_{2} \mathrm{O}}\right)\left[\mathrm{C}_{\mathrm{H}_{2} \mathrm{O}}=\mathrm{V}-\mathrm{C}_{\mathrm{osm}}\right]$. All of the others will have a positive $\mathrm{C}_{\mathrm{H}_{2} \mathrm{O}}$ because they are producing hyposmotic urine as a result of the suppression of antidiuretic hormone (ADH) by water drinking, central diabetes insipidus, or nephrogenic diabetes insipidus.

A Negative Free-Water Clearance (−CH2O)\left(-\mathrm{C}_{\mathrm{H}_{2} \mathrm{O}}\right)(−CH2​O​) Will Occur in a Person Who A) Drinks

A Negative Free-Water Clearance $\left(-\mathrm{C}_{\mathrm{H}_{2} \mathrm{O}}\right)$ Will Occur in a Person Who
A) Drinks