Use the following to answer the questions below:
Robins are common birds in North America. Suppose that the wingspan of robins is approximately normal with mean 14 inches and standard deviation 0.7 inches.
-The largest 20% of robins have wingspans longer than what value? Report your answer with two decimal places.
A) 14.59 inches
B) 14.87 inches
C) 14.32 inches
D) 13.79 inches

Question

Quizplus · Accepted Answer

To find the wingspan that separates the largest 20% of robins, we need to find the 80th percentile of a normal distribution with mean 14 and standard deviation 0.7. Using a standard normal distribution table or calculator, the z-score for the 80th percentile is approximately 0.84. Applying the formula: wingspan = mean + (z-score * standard deviation), we get 14 + (0.84 * 0.7) = 14.588, which rounds to 14.59 inches.

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