The most efficient way to implement an array-based stack keeps the top of the stack at the position 0 of the array?

Question

Quizplus · Accepted Answer

Keeping the top of the stack at position 0 means that every time an item is pushed onto the stack or popped off, all other elements must be shifted, which is inefficient. It's more efficient to keep the top at the end of the array, where no shifting is required for push and pop operations.

The Most Efficient Way to Implement an Array-Based Stack Keeps