Consider the difference equation = 0.50 + 6, n = 0, 1, 2, 3...Find the explicit solution of this difference equation in terms of .
A) $ y_{n}=0.50^{n} y_{0}+12, n=0,1,2,3 \ldots $
B) $ y_{n}=0.50^{n} y_{0}+4, n=0,1,2,3 \ldots $
C) $ y_{n}=0.50^{n-1} y_{0}+6, n=0,1,2,3 \ldots $
D) $ y_{n}=0.50^{n-1} y_{0}+12, n=0,1,2,3 \ldots $

Question

Consider the difference equation  = 0.50  + 6, n = 0, 1, 2, 3...Find the explicit solution of this difference equation in terms of  .
A) $ y_{n}=0.50^{n} y_{0}+12, n=0,1,2,3 \ldots $ 
B) $ y_{n}=0.50^{n} y_{0}+4, n=0,1,2,3 \ldots $ 
C) $ y_{n}=0.50^{n-1} y_{0}+6, n=0,1,2,3 \ldots $ 
D) $ y_{n}=0.50^{n-1} y_{0}+12, n=0,1,2,3 \ldots $

Quizplus · Accepted Answer

The Answer of Consider the difference equation  = 0.50  + 6, n = 0, 1, 2, 3...Find the explicit solution of this difference equation in terms of  .
A) $ y_{n}=0.50^{n} y_{0}+12, n=0,1,2,3 \ldots $ 
B) $ y_{n}=0.50^{n} y_{0}+4, n=0,1,2,3 \ldots $ 
C) $ y_{n}=0.50^{n-1} y_{0}+6, n=0,1,2,3 \ldots $ 
D) $ y_{n}=0.50^{n-1} y_{0}+12, n=0,1,2,3 \ldots $

Consider the Difference Equation = 0 yn=0.50ny0+12,n=0,1,2,3… y_{n}=0.50^{n} y_{0}+12, n=0,1,2,3 \ldots yn​=0.50ny0​+12,n=0,1,2,3…

Consider the Difference Equation = 0 $y_{n}=0.50^{n} y_{0}+12, n=0,1,2,3 \ldots$