Factor.
-$25 z^{4}-5 z^{2}-12$
A) $\left(5 z^{4}+3\right)(5 z-4)$
B) $\left(5 z^{2}+3\right)\left(5 z^{2}-4\right)$
C) $\left(5 z^{4}+4\right)(5 z-3)$
D) $\left(5 z^{2}+4\right)\left(5 z^{2}-3\right)$

Question

Quizplus · Accepted Answer

The correct factorization of $25z^4 - 5z^2 - 12$ is achieved by finding two numbers that multiply to $25 \times -12 = -300$ and add to $-5$. These numbers are $+15$ and $-20$, leading to the factorization $(5z^2 + 3)(5z^2 - 4)$.

Factor - 25z4−5z2−1225 z^{4}-5 z^{2}-1225z4−5z2−12 A) (5z4+3)(5z−4)\left(5 z^{4}+3\right)(5 z-4)(5z4+3)(5z−4) B) (5z2+3)(5z2−4)\left(5 z^{2}+3\right)\left(5 z^{2}-4\right)(5z2+3)(5z2−4)

Factor
- $25 z^{4}-5 z^{2}-12$ A) $\left(5 z^{4}+3\right)(5 z-4)$ B) $\left(5 z^{2}+3\right)\left(5 z^{2}-4\right)$