Find the reciprocal.
-$\frac{y^{2}+5 y+8}{y^{2}-y+4}$
A) $\frac{y^{2}+5 y-8}{y^{2}-y-4}$
B) $\frac{y^{2}-y+4}{y^{2}+5 y+8}$
C) $\frac{y^{2}-8 y+5}{y^{2}+y+4}$
D) $\frac{y^{2}-y-4}{y^{2}+5 y-8}$

Question

Quizplus · Accepted Answer

The reciprocal of a fraction is obtained by swapping its numerator and denominator. Therefore, the reciprocal of $\frac{y^{2}+5 y+8}{y^{2}-y+4}$ is $\frac{y^{2}-y+4}{y^{2}+5 y+8}$.

Find the Reciprocal y2+5y+8y2−y+4\frac{y^{2}+5 y+8}{y^{2}-y+4}y2−y+4y2+5y+8​ A) y2+5y−8y2−y−4\frac{y^{2}+5 y-8}{y^{2}-y-4}y2−y−4y2+5y−8​ B) y2−y+4y2+5y+8\frac{y^{2}-y+4}{y^{2}+5 y+8}y2+5y+8y2−y+4​ C) y2−8y+5y2+y+4\frac{y^{2}-8 y+5}{y^{2}+y+4}y2+y+4y2−8y+5​

Find the Reciprocal $\frac{y^{2}+5 y+8}{y^{2}-y+4}$ A) $\frac{y^{2}+5 y-8}{y^{2}-y-4}$ B) $\frac{y^{2}-y+4}{y^{2}+5 y+8}$ C) $\frac{y^{2}-8 y+5}{y^{2}+y+4}$