Solve the equation.
-$\frac{\mathrm{x}}{\mathrm{x}+1}-\frac{1}{\mathrm{x}-1}=\frac{\mathrm{x}^{2}+1}{\mathrm{x}^{2}-1}$
A) $-1,1$
B) - 1
C) No solution
D) 1

Question

Quizplus · Accepted Answer

The equation simplifies to an identity that holds for all x except where the original equation is undefined. The original equation is undefined for x = 1 and x = -1 because these values make the denominators zero. Therefore, there is no specific solution set beyond these restrictions, leading to the conclusion that there are no solutions within the domain of the original equation.

Solve the Equation xx+1−1x−1=x2+1x2−1\frac{\mathrm{x}}{\mathrm{x}+1}-\frac{1}{\mathrm{x}-1}=\frac{\mathrm{x}^{2}+1}{\mathrm{x}^{2}-1}x+1x​−x−11​=x2−1x2+1​ A) −1,1-1,1−1,1 B) - 1 C) No Solution D) 1

Solve the Equation $\frac{\mathrm{x}}{\mathrm{x}+1}-\frac{1}{\mathrm{x}-1}=\frac{\mathrm{x}^{2}+1}{\mathrm{x}^{2}-1}$ A) $-1,1$ B) - 1
C) No Solution
D) 1