Solve the equation.
-$\sqrt{\mathrm{p}^{2}-5 \mathrm{p}+81}=\mathrm{p}+4$
A) $\frac{-5}{2}$
B) 9
C) 5
D) -5

Question

Quizplus · Accepted Answer

Squaring both sides of the equation gives $\mathrm{p}^{2}-5 \mathrm{p}+81=(\mathrm{p}+4)^{2}$, which simplifies to $\mathrm{p}^{2}-5 \mathrm{p}+81=\mathrm{p}^{2}+8 \mathrm{p}+16$. Subtracting $\mathrm{p}^{2}$ and $\mathrm{p}$ from both sides gives $-5 \mathrm{p}+81=8 \mathrm{p}+16$, which simplifies to $-13 \mathrm{p}=-65$. Dividing both sides by $-13$ gives $\mathrm{p}=5$.

Solve the Equation p2−5p+81=p+4\sqrt{\mathrm{p}^{2}-5 \mathrm{p}+81}=\mathrm{p}+4p2−5p+81​=p+4 A) −52\frac{-5}{2}2−5​ B) 9 C) 5 D) -5

Solve the Equation $\sqrt{\mathrm{p}^{2}-5 \mathrm{p}+81}=\mathrm{p}+4$ A) $\frac{-5}{2}$ B) 9
C) 5
D) -5