If 30.0 mL of 0.40 M H₂SO₄ is required to neutralize 15.0 mL of NaOH, the molarity of the NaOH solution is ________.
H₂SO₄ (aq) + 2 NaOH (aq) $\rightarrow$ Na₂SO₄ (aq) + 2 H₂O (l)

Question

If 30.0 mL of 0.40 M H₂SO₄ is required to neutralize 15.0 mL of NaOH, the molarity of the NaOH solution is ________. H₂SO₄ (aq) + 2 NaOH (aq) $\rightarrow$Na₂SO₄ (aq) + 2 H₂O (l)

Quizplus · Accepted Answer

Given the balanced chemical equation, 1 mole of H₂ reacts with 2 moles of NaOH. The moles of H₂ used are $30.0 \, \text{mL} \times 0.40 \, \text{M} = 0.012 \, \text{moles}$. Since it reacts in a 1:2 ratio with NaOH, the moles of NaOH are $0.012 \times 2 = 0.024 \, \text{moles}$. The molarity of NaOH is then $0.024 \, \text{moles} / 0.015 \, \text{L} = 1.6 \, \text{M}$.

If 300 ML of 0 →\rightarrow→ Na2SO4 (Aq) + 2 H2O (L) A) 1

If 300 ML of 0 $\rightarrow$ Na₂SO₄ (Aq) + 2 H₂O (L)
A) 1