The concentration of Cu²⁺ ions in a river water sample is found to be 3.26 micrograms of Cu²⁺ ions per 0.250 kg of river water. Express the concentration of Cu²⁺ ions in ppb (m/m).

Question

Quizplus · Accepted Answer

To convert the concentration to ppb (parts per billion, m/m), we use the formula: concentration in ppb = (mass of solute in micrograms / mass of solution in kilograms) x 10^6. Here, mass of solute = 3.26 micrograms, mass of solution = 0.250 kg. Thus, concentration in ppb = (3.26 / 0.250) x 10^6 = 13.04 ppb, which rounds to 13.0 ppb.

The Concentration of Cu2+ Ions in a River Water Sample

The Concentration of Cu²⁺ Ions in a River Water Sample