In the reaction Fe₂O₃ + 3H₂ $\rightarrow$ 2Fe + 3H₂O, how many grams of Fe₂O₃ must react to produce 10.8 liters of H₂O at STP?

Question

Quizplus · Accepted Answer

At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters. The reaction shows that 1 mole of FeS₂O₃ produces 3 moles of H₂SO₄. To produce 10.8 liters of H₂SO₄, which is 10.8 / 22.4 = 0.482 moles, we need 0.482 / 3 = 0.161 moles of FeS₂O₃. The molar mass of FeS₂O₃ is approximately 160 g/mol (56 for Fe, 64 for 2S, and 48 for 3O), so the mass required is 0.161 moles * 160 g/mol = 25.76 g, which rounds to 25.7 g.

In the Reaction Fe2O3 + 3H2 →\rightarrow→ 2Fe + 3H2O, How Many Grams of Fe2O3 Must React

In the Reaction Fe₂O₃ + 3H₂ $\rightarrow$ 2Fe + 3H₂O, How Many Grams of Fe₂O₃ Must React