A mixture of 8.95 g of Cl₂ and 18.0 g of NO₂ and an undetermined amount of SO₂ occupies a volume of 22.4 liters at 760 mm Hg and 0 °C. How many moles of SO₂ are present?

Question

Quizplus · Accepted Answer

At 0 °C and 760 mm Hg, 22.4 liters of gas is equivalent to 1 mole according to the ideal gas law. The moles of Cl₂ and N₂O can be calculated using their molar masses (Cl₂ = 70.90 g/mol, N₂O = 44.01 g/mol). For Cl₂: 8.95 g / 70.90 g/mol = 0.126 moles. For N₂O: 18.0 g / 44.01 g/mol = 0.409 moles. The total moles before considering SO₂ is 0.126 + 0.409 = 0.535 moles. Since the total is 1 mole, the moles of SO₂ are 1 - 0.535 = 0.465 moles, which is closest to the provided option D) 0.483 moles.

A Mixture of 8