In a certain experiment 24.9 g of NH4NO3 (molar mass = 80.06) was produced from 27.2 g of Fe(NO3) 3 (molar mass = 241.87) reacting with an excess of NH3 and H2O according to the equation
Fe(NO3) 3 + 3 NH3 + 3 H2O Fe(OH) 3 + 3 NH4NO3
What is, respectively, the theoretical yield and percent yield of NH4NO3?
A) 5.53 g and 42.1%
B) 13.5 g and 83.7%
C) 16.6 g and 31.7%
D) 27.0 g and 92.2%
Correct Answer:
Verified
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