A mixture contains 0.75 moles of BaCO₃ and 0.55 moles of Li₂CO₃. When this mixture is strongly heated both carbonates completely decompose to oxides and carbon dioxide as shown by the equations:
BaCO₃ ? BaO + CO₂
Li₂CO₃ $\rightarrow$ Li₂O + CO₂
How many moles of CO₂ are produced from the decomposition?

Question

A mixture contains 0.75 moles of BaCO₃ and 0.55 moles of Li₂CO₃. When this mixture is strongly heated both carbonates completely decompose to oxides and carbon dioxide as shown by the equations:
BaCO₃ ? BaO + CO₂
Li₂CO₃

\rightarrow

Li₂O + CO₂
How many moles of CO₂ are produced from the decomposition?

Quizplus · Accepted Answer

The decomposition of 0.75 moles of BaCO3 produces 0.75 moles of CO2, and the decomposition of 0.55 moles of Li2CO3 produces 0.55 moles of CO2. Adding these together gives 0.75 + 0.55 = 1.30 moles of CO2.

A Mixture Contains 0 →\rightarrow→ Li2O + CO2 How Many Moles of CO2 Are Produced

A Mixture Contains 0 $\rightarrow$ Li₂O + CO₂
How Many Moles of CO₂ Are Produced