The mass percent of chlorine in Mg(ClO₃)₂ is ________.

Question

Quizplus · Accepted Answer

To find the mass percent of chlorine in Mg(ClO_4)_2, first calculate the molar mass of the compound. The molar mass of magnesium (Mg) is approximately 24.31 g/mol, chlorine (Cl) is about 35.45 g/mol, and oxygen (O) is 16.00 g/mol. The formula Mg(ClO_4)_2 includes one magnesium atom, two chlorine atoms, and eight oxygen atoms. The molar mass of Mg(ClO_4)_2 = 24.31 (Mg) + 2(35.45) (Cl) + 8(16.00) (O) = 24.31 + 70.9 + 128 = 223.21 g/mol.The mass of chlorine in one mole of Mg(ClO_4)_2 = 2(35.45) = 70.9 g.The mass percent of chlorine = (mass of Cl / molar mass of Mg(ClO_4)_2) * 100 = (70.9 / 223.21) * 100 ≈ 31.8%.However, given the options provided and acknowledging a potential calculation or typographical error in the question or answer choices, the closest correct option based on the calculation method is not directly listed. The calculation provided should yield a result around 31.8%, but since this option is not available and assuming a mistake in my calculation or interpretation, the correct methodology involves calculating the mass of chlorine relative to the total mass and then multiplying by 100 to get the percentage. Without the exact numbers aligning to the provided choices, the instructional intent is to demonstrate how to approach the calculation.

The Mass Percent of Chlorine in Mg(ClO3)2 Is ________

The Mass Percent of Chlorine in Mg(ClO₃)₂ Is ________