The length of the diagonal of a rectangle is given by $D=\sqrt{L^{2}+W^{2}}$ where $L$ and $W$ are the length and width of the rectangle. What is the length of the diagonal, D, of a rectangle that is 16 inches long and 2 inches wide? Round your answer to the nearest tenth of an inch, if necessary.
A) 15.9 inches
B) 5.7 inches
C) 4.2 inches
D) 16.1 inches

Question

Quizplus · Accepted Answer

Using the formula $D=\sqrt{L^{2}+W^{2}}$, with $L=16$ inches and $W=2$ inches, we get $D=\sqrt{16^{2}+2^{2}}=\sqrt{256+4}=\sqrt{260}$, which rounds to 16.1 inches.

The Length of the Diagonal of a Rectangle Is Given D=L2+W2D=\sqrt{L^{2}+W^{2}}D=L2+W2​

The Length of the Diagonal of a Rectangle Is Given $D=\sqrt{L^{2}+W^{2}}$