Factor completely
-$x^{5 / 2}-2 x^{3 / 2}-35 x^{1 / 2}$
A) $x^{1 / 2}(x-5)(x+7)$
B) $x^{1 / 2}(x-5)(x-7)$
C) $x^{1 / 2}(x+5)(x+7)$
D) $x^{1 / 2}(x+5)(x-7)$

Name: Factor completely -$x^{5 / 2}-2 x^{3 / 2}-35 x^{1 / 2}$ A) $x^{1 / 2}(x-5)(x+7)$ B) $x^{1 / 2}(x-5)(x-7)$ C) $x^{1 / 2}(x+5)(x+7)$ D) $x^{1 / 2}(x+5)(x-7)$
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Question

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The Answer of Factor completely
-$x^{5 / 2}-2 x^{3 / 2}-35 x^{1 / 2}$
A) $x^{1 / 2}(x-5)(x+7)$
B) $x^{1 / 2}(x-5)(x-7)$
C) $x^{1 / 2}(x+5)(x+7)$
D) $x^{1 / 2}(x+5)(x-7)$

Factor Completely - x5/2−2x3/2−35x1/2x^{5 / 2}-2 x^{3 / 2}-35 x^{1 / 2}x5/2−2x3/2−35x1/2

Factor Completely
- $x^{5 / 2}-2 x^{3 / 2}-35 x^{1 / 2}$