Solve the equation by completing the square
-$\mathrm{x}^{2}-4 \mathrm{x}-5=0$
A) $\{ \pm \sqrt{-5}\}$
B) $\{5,-1\}$
C) $\{-4,-1\}$
D) $\{-5,1\}$

Question

Quizplus · Accepted Answer

To solve the equation $x^2 - 4x - 5 = 0$ by completing the square, we first move the constant term to the other side: $x^2 - 4x = 5$. Then, we add $(\frac{-4}{2})^2 = 4$ to both sides to complete the square: $x^2 - 4x + 4 = 9$. This gives us $(x - 2)^2 = 9$, so $x - 2 = \pm 3$. Solving for $x$ gives $x = 2 \pm 3$, which results in $x = 5$ or $x = -1$.

Solve the Equation by Completing the Square - x2−4x−5=0\mathrm{x}^{2}-4 \mathrm{x}-5=0x2−4x−5=0 A) {±−5}\{ \pm \sqrt{-5}\}{±−5​}

Solve the Equation by Completing the Square
- $\mathrm{x}^{2}-4 \mathrm{x}-5=0$ A) $\{ \pm \sqrt{-5}\}$