Solve by using the quadratic formula
-$x^{2}+2 x-48=0$
A) $\{-8,-6\}$
B) $\{-8,6\}$
C) $\{-6,8\}$
D) $\{8,6\}$.

Question

Quizplus · Accepted Answer

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$, where $a=1$, $b=2$, and $c=-48$. Plugging these values in gives $x = \frac{-2 \pm \sqrt{2^2-4(1)(-48)}}{2(1)} = \frac{-2 \pm \sqrt{4+192}}{2} = \frac{-2 \pm \sqrt{196}}{2} = \frac{-2 \pm 14}{2}$, which simplifies to $x = -8$ or $x = 6$.

Solve by Using the Quadratic Formula - x2+2x−48=0x^{2}+2 x-48=0x2+2x−48=0 A) {−8,−6}\{-8,-6\}{−8,−6} B) {−8,6}\{-8,6\}{−8,6}

Solve by Using the Quadratic Formula
- $x^{2}+2 x-48=0$ A) $\{-8,-6\}$ B) $\{-8,6\}$