For the given quadratic equation, use the discriminant to determine the number and type of solutions.
-$x^{2}+2 x-5=0$
A) Two nonreal complex
B) One real
C) Two real

Question

Quizplus · Accepted Answer

The discriminant of a quadratic equation $ax^2 + bx + c = 0$ is given by $D = b^2 - 4ac$. For the given equation, $a = 1$, $b = 2$, and $c = -5$, so $D = 2^2 - 4(1)(-5) = 4 + 20 = 24$. Since $D > 0$, the equation has two real solutions.

For the Given Quadratic Equation, Use the Discriminant to Determine x2+2x−5=0x^{2}+2 x-5=0x2+2x−5=0

For the Given Quadratic Equation, Use the Discriminant to Determine $x^{2}+2 x-5=0$