Find the vertex of the parabola associated with the quadratic equation.
-$y=x^{2}+2 x+8$
A) $(1,8)$
B) $(-1,7)$
C) $(-1,8)$
D) $(1,7)$

Question

Quizplus · Accepted Answer

The vertex of a parabola in the form $y = ax^2 + bx + c$ can be found using the formula $(-b/2a, f(-b/2a))$. For $y = x^2 + 2x + 8$, $a = 1$, $b = 2$, so the x-coordinate of the vertex is $-2/(2*1) = -1$. Plugging $-1$ back into the equation gives $y = (-1)^2 + 2(-1) + 8 = 7$. Therefore, the vertex is $(-1, 7)$.

Find the Vertex of the Parabola Associated with the Quadratic y=x2+2x+8y=x^{2}+2 x+8y=x2+2x+8

Find the Vertex of the Parabola Associated with the Quadratic $y=x^{2}+2 x+8$