Find the vertex by completing the square.
-$y=x^{2}+3 x-17$
A) $\left(\frac{3}{2}, \frac{59}{4}\right)$

B) $\left(\frac{3}{2},-\frac{77}{4}\right)$

C) $\left(-\frac{3}{2}, \frac{59}{4}\right)$

D) $\left(-\frac{3}{2},-\frac{77}{4}\right)$

Question

Find the vertex by completing the square.
-$y=x^{2}+3 x-17$
A) $\left(\frac{3}{2}, \frac{59}{4}\right)$

B) $\left(\frac{3}{2},-\frac{77}{4}\right)$

C) $\left(-\frac{3}{2}, \frac{59}{4}\right)$

D) $\left(-\frac{3}{2},-\frac{77}{4}\right)$

Quizplus · Accepted Answer

To complete the square, rewrite $y = x^2 + 3x - 17$ as $y = (x^2 + 3x + \frac{9}{4}) - \frac{9}{4} - 17$. This simplifies to $y = (x + \frac{3}{2})^2 - \frac{77}{4}$. The vertex is $(- \frac{3}{2}, - \frac{77}{4})$.

Find the Vertex by Completing the Square y=x2+3x−17y=x^{2}+3 x-17y=x2+3x−17 A) (32,594)\left(\frac{3}{2}, \frac{59}{4}\right)(23​,459​)

Find the Vertex by Completing the Square $y=x^{2}+3 x-17$ A) $\left(\frac{3}{2}, \frac{59}{4}\right)$