Find the vertex
-$f(x)=x^{2}-7$
A) $(7,0)$
B) $(0,-7)$
C) $(-7,0)$
D) $(0,7)$

Name: Find the vertex -$f(x)=x^{2}-7$ A) $(7,0)$ B) $(0,-7)$ C) $(-7,0)$ D) $(0,7)$
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Question

Quizplus · Accepted Answer

The vertex of a parabola in the form $f(x) = ax^2 + bx + c$ is given by $(-b/2a, f(-b/2a))$. For $f(x) = x^2 - 7$, $a = 1$, $b = 0$, so the vertex is at $x = -b/2a = 0$. Plugging $x = 0$ into $f(x)$, we get $f(0) = 0^2 - 7 = -7$, so the vertex is $(0, -7)$.

Find the Vertex - f(x)=x2−7f(x)=x^{2}-7f(x)=x2−7 A) (7,0)(7,0)(7,0) B) (0,−7)(0,-7)(0,−7) C) (−7,0)(-7,0)(−7,0) D) (0,7)(0,7)(0,7)

Find the Vertex
- $f(x)=x^{2}-7$ A) $(7,0)$ B) $(0,-7)$ C) $(-7,0)$ D) $(0,7)$