Solved

Graph the Piecewise Function
- $f(x)= \begin{cases}x-3 & \text { if } x<0 \\ (x-1)^{3}+4 & \text { if } 0 \leq x \leq 2 \\ |x-5|-4 & \text { if } x>2\end{cases}$

Question 263

Multiple Choice

Graph the piecewise function
- $f(x) = \begin{cases}x-3 & \text { if } x<0 \\ (x-1) ^{3}+4 & \text { if } 0 \leq x \leq 2 \\ |x-5|-4 & \text { if } x>2\end{cases}$

A)
$Graph the piecewise function - f(x) = \begin{cases}x-3 & \text { if } x<0 \\ (x-1) ^{3}+4 & \text { if } 0 \leq x \leq 2 \\ |x-5|-4 & \text { if } x>2\end{cases} A) B) C) D)$
B)
$Graph the piecewise function - f(x) = \begin{cases}x-3 & \text { if } x<0 \\ (x-1) ^{3}+4 & \text { if } 0 \leq x \leq 2 \\ |x-5|-4 & \text { if } x>2\end{cases} A) B) C) D)$
C)
$Graph the piecewise function - f(x) = \begin{cases}x-3 & \text { if } x<0 \\ (x-1) ^{3}+4 & \text { if } 0 \leq x \leq 2 \\ |x-5|-4 & \text { if } x>2\end{cases} A) B) C) D)$
D)
$Graph the piecewise function - f(x) = \begin{cases}x-3 & \text { if } x<0 \\ (x-1) ^{3}+4 & \text { if } 0 \leq x \leq 2 \\ |x-5|-4 & \text { if } x>2\end{cases} A) B) C) D)$