A bowling alley charges $\$ 2.60$ for shoes plus $\$ 2.75$ per game bowled. Let $C(g)$ be the total cost for bowling $g$ games (including shoe rental). Now suppose the bowling alley decides to increase the cost for shoes by $\$ 2.00$ and include the first game for free. What is the formula for the new total cost, $N(g)$, of bowling $g$ games as a transformation of $C(g)$ ?
A) $ N(g)=C(g-2.75)+4.60$
B) $ N(g)=C(g-1)+2.00$
C) $ N(g)=C(g-1)+4.60$
D) $ N(g)=C(g+1.75)+2.00$

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The Answer of A bowling alley charges $\$ 2.60$ for shoes plus $\$ 2.75$ per game bowled. Let $C(g)$ be the total cost for bowling $g$ games (including shoe rental). Now suppose the bowling alley decides to increase the cost for shoes by $\$ 2.00$ and include the first game for free. What is the formula for the new total cost, $N(g)$, of bowling $g$ games as a transformation of $C(g)$ ?
A) $ N(g)=C(g-2.75)+4.60$
B) $ N(g)=C(g-1)+2.00$
C) $ N(g)=C(g-1)+4.60$
D) $ N(g)=C(g+1.75)+2.00$

A Bowling Alley Charges $2.60\$ 2.60$2.60 For Shoes Plus $2.75\$ 2.75$2.75 Per Game Bowled

A Bowling Alley Charges $\$ 2.60$ For Shoes Plus $\$ 2.75$ Per Game Bowled