If $-\frac{\pi}{2} \leq t \leq \frac{\pi}{2}$, in what quadrant is $\sin t=0.61$ ?
A) I
B) II
C) III
D) IV

Name: If $-\frac{\pi}{2} \leq t \leq \frac{\pi}{2}$, in what quadrant is $\sin t=0.61$ ? A) I B) II C) III D) IV
Brand: Quizplus
Rating: 4.9 (40 reviews)

Question

Quizplus · Accepted Answer

$\sin t=0.61$ is positive, so $t$ must be in quadrant I or II. Since $-\frac{\pi}{2} \leq t \leq \frac{\pi}{2}$, $t$ must be in quadrant I.

If −π2≤t≤π2-\frac{\pi}{2} \leq t \leq \frac{\pi}{2}−2π​≤t≤2π​ , in What Quadrant Is sin⁡t=0.61\sin t=0.61sint=0.61

If $-\frac{\pi}{2} \leq t \leq \frac{\pi}{2}$ , in What Quadrant Is $\sin t=0.61$