The mean score on a physiology test was 71, and the standard deviation of scores was 9. Assuming a normal distribution, what percentage of scores fell below a 60?
A) 11.12%
B) 19.44%
C) 25%
D) 45.71%

Question

Quizplus · Accepted Answer

To find the percentage of scores below 60, we calculate the z-score: z = (60 - 71) / 9 = -1.22. Using a standard normal distribution table, a z-score of -1.22 corresponds to approximately 11.12% of scores falling below 60.

The Mean Score on a Physiology Test Was 71, and the Standard