Factor.
-$8 y^{2}+36 y-20$
A) $(2 y-1)(4 y+20)$
B) $(8 y-4)(y+5)$
C) $4(2 y+1)(y-5)$
D) $4(2 y-1)(y+5)$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is 4, to get $4(2y^2 + 9y - 5)$. Then, find factors of -10 (the product of 2 and -5) that add up to 9, which are 10 and -1. Use these to split the middle term and factor by grouping, resulting in $4(2y^2 + 10y - y - 5) = 4((2y^2 + 10y) - (y + 5)) = 4(2y(y + 5) - 1(y + 5)) = 4(2y - 1)(y + 5)$.

Factor - 8y2+36y−208 y^{2}+36 y-208y2+36y−20 A) (2y−1)(4y+20)(2 y-1)(4 y+20)(2y−1)(4y+20) B) (8y−4)(y+5)(8 y-4)(y+5)(8y−4)(y+5) C) 4(2y+1)(y−5)4(2 y+1)(y-5)4(2y+1)(y−5)

Factor
- $8 y^{2}+36 y-20$ A) $(2 y-1)(4 y+20)$ B) $(8 y-4)(y+5)$ C) $4(2 y+1)(y-5)$