Factor completely.
-$36 x^{2}+84 x+49$
A) $(6 x+7)^{2}$
B) $(6 x-7)^{2}$
C) $(6 x+7)(6 x-7)$
D) Prime

Name: Factor completely. -$36 x^{2}+84 x+49$ A) $(6 x+7)^{2}$ B) $(6 x-7)^{2}$ C) $(6 x+7)(6 x-7)$ D) Prime
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Question

Quizplus · Accepted Answer

This is a perfect square trinomial. It can be factored as $(6x+7)^2$ because $36x^2$ is the square of $6x$, $49$ is the square of $7$, and $2 \times 6x \times 7 = 84x$, which matches the middle term.

Factor Completely 36x2+84x+4936 x^{2}+84 x+4936x2+84x+49 A) (6x+7)2(6 x+7)^{2}(6x+7)2 B) (6x−7)2(6 x-7)^{2}(6x−7)2 C) (6x+7)(6x−7)(6 x+7)(6 x-7)(6x+7)(6x−7)

Factor Completely $36 x^{2}+84 x+49$ A) $(6 x+7)^{2}$ B) $(6 x-7)^{2}$ C) $(6 x+7)(6 x-7)$