Solve the problem.
-If an object is thrown upward with an initial velocity of $64 \mathrm{ft} / \mathrm{sec}$, its height after $\mathrm{t} \mathrm{sec}$ is given by $h=64 t-16 t^{2}$. Find the number of seconds before the object hits the ground.
A) $32 \mathrm{sec}$
B) $2 \mathrm{sec}$
C) $4 \mathrm{sec}$
D) $48 \mathrm{sec}$

Question

Quizplus · Accepted Answer

To find when the object hits the ground, set $h = 0$ and solve for $t$: $0 = 64t - 16t^2$. Factoring out $16t$, we get $16t(4 - t) = 0$, which gives $t = 0$ (when it was thrown) and $t = 4$ seconds (when it hits the ground).

Solve the Problem 64ft/sec64 \mathrm{ft} / \mathrm{sec}64ft/sec , Its Height After tsec\mathrm{t} \mathrm{sec}tsec

Solve the Problem $64 \mathrm{ft} / \mathrm{sec}$ , Its Height After $\mathrm{t} \mathrm{sec}$