Simplify.
-$\frac{y^{2}-2 y-8}{y^{2}+3 y-28}$
A) $\frac{-2 y-8}{3 y-28}$
B) $\frac{-2 y-2}{3 y-7}$
C) $\frac{y+2}{y+7}$
D) $-\frac{y^{2}-2 y-8}{y^{2}+3 y-28}$

Question

Quizplus · Accepted Answer

The expression can be simplified by factoring both the numerator and the denominator. The numerator $y^2 - 2y - 8$ factors into $(y - 4)(y + 2)$, and the denominator $y^2 + 3y - 28$ factors into $(y + 7)(y - 4)$. After canceling the common factor $(y - 4)$, the simplified form is $\frac{y + 2}{y + 7}$.

Simplify - y2−2y−8y2+3y−28\frac{y^{2}-2 y-8}{y^{2}+3 y-28}y2+3y−28y2−2y−8​ A) −2y−83y−28\frac{-2 y-8}{3 y-28}3y−28−2y−8​ B) −2y−23y−7\frac{-2 y-2}{3 y-7}3y−7−2y−2​

Simplify
- $\frac{y^{2}-2 y-8}{y^{2}+3 y-28}$ A) $\frac{-2 y-8}{3 y-28}$ B) $\frac{-2 y-2}{3 y-7}$