Find the LCM.
-$x^{2}-8 x+16, x^{2}-3 x-4$
A) $(x-4)(x+1)$
B) $(x+4)(x+4)(x+1)$
C) $(x-4)(x-4)$
D) $(x-4)(x-4)(x+1)$

Name: Find the LCM. -$x^{2}-8 x+16, x^{2}-3 x-4$ A) $(x-4)(x+1)$ B) $(x+4)(x+4)(x+1)$ C) $(x-4)(x-4)$ D) $(x-4)(x-4)(x+1)$
Brand: Quizplus
Rating: 4.8 (41 reviews)

Question

Quizplus · Accepted Answer

The LCM of two polynomials is the product of their factors, using the highest power of common factors. Factorizing the given polynomials: $x^{2}-8x+16=(x-4)^2$ and $x^{2}-3x-4=(x-4)(x+1)$. The LCM is $(x-4)^2(x+1)$, which matches option D.

Find the LCM x2−8x+16,x2−3x−4x^{2}-8 x+16, x^{2}-3 x-4x2−8x+16,x2−3x−4 A) (x−4)(x+1)(x-4)(x+1)(x−4)(x+1) B) (x+4)(x+4)(x+1)(x+4)(x+4)(x+1)(x+4)(x+4)(x+1) C) (x−4)(x−4)(x-4)(x-4)(x−4)(x−4) D) (x−4)(x−4)(x+1)(x-4)(x-4)(x+1)(x−4)(x−4)(x+1)

Find the LCM $x^{2}-8 x+16, x^{2}-3 x-4$ A) $(x-4)(x+1)$ B) $(x+4)(x+4)(x+1)$ C) $(x-4)(x-4)$ D) $(x-4)(x-4)(x+1)$