Simplify.
-$\frac{\frac{1}{m}+\frac{1}{z}}{\frac{1}{m}-\frac{1}{z}}$
A) $\frac{z-m}{z}$
B) $\frac{z+m}{z}$
C) $\frac{z+m}{m}$
D) $\frac{z+m}{z-m}$

Question

Quizplus · Accepted Answer

To simplify $\frac{\frac{1}{m}+\frac{1}{z}}{\frac{1}{m}-\frac{1}{z}}$, we find a common denominator for the fractions in the numerator and the denominator, which is $mz$. This gives us $\frac{\frac{z+m}{mz}}{\frac{z-m}{mz}}$. Simplifying further, the $mz$ in the numerator and denominator cancel out, leaving us with $\frac{z+m}{z-m}$.

Simplify - 1m+1z1m−1z\frac{\frac{1}{m}+\frac{1}{z}}{\frac{1}{m}-\frac{1}{z}}m1​−z1​m1​+z1​​ A) z−mz\frac{z-m}{z}zz−m​ B) z+mz\frac{z+m}{z}zz+m​ C) z+mm\frac{z+m}{m}mz+m​ D) z+mz−m\frac{z+m}{z-m}z−mz+m​

Simplify
- $\frac{\frac{1}{m}+\frac{1}{z}}{\frac{1}{m}-\frac{1}{z}}$ A) $\frac{z-m}{z}$ B) $\frac{z+m}{z}$ C) $\frac{z+m}{m}$ D) $\frac{z+m}{z-m}$