Solve the equation.
-$\frac{1}{\mathrm{y}+3}-\frac{8}{\mathrm{y}-3}=\frac{8}{\mathrm{y}^{2}-9}$
A) $\sqrt{9}$
B) 35
C) 5
D) -5

Question

Quizplus · Accepted Answer

The equation can be simplified by recognizing that $\mathrm{y}^2 - 9$ is a difference of squares, $(\mathrm{y}+3)(\mathrm{y}-3)$. Multiplying through by $(\mathrm{y}+3)(\mathrm{y}-3)$ eliminates the denominators, leading to a simplified equation that can be solved for $\mathrm{y}$. Solving gives $\mathrm{y} = -5$.

Solve the Equation 1y+3−8y−3=8y2−9\frac{1}{\mathrm{y}+3}-\frac{8}{\mathrm{y}-3}=\frac{8}{\mathrm{y}^{2}-9}y+31​−y−38​=y2−98​ A) 9\sqrt{9}9​ B) 35 C) 5 D) -5

Solve the Equation $\frac{1}{\mathrm{y}+3}-\frac{8}{\mathrm{y}-3}=\frac{8}{\mathrm{y}^{2}-9}$ A) $\sqrt{9}$ B) 35
C) 5
D) -5