Solve the problem.
-The distance $D$ that a spring is stretched by a hanging object varies directly as the weight $W$ of the object. If a $19-\mathrm{kg}$ object stretches a spring $10 \mathrm{~cm}$, find the distance when the weight is $29-\mathrm{kg}$.
A) $15.26 \mathrm{~cm}$
B) $55.1 \mathrm{~cm}$
C) $58 \mathrm{~cm}$
D) $0.53 \mathrm{~cm}$

Question

Quizplus · Accepted Answer

The relationship between the distance $D$ and the weight $W$ is direct, so $D = k \cdot W$, where $k$ is the constant of proportionality. Given $D = 10$ cm for $W = 19$ kg, we find $k = \frac{10}{19}$. For $W = 29$ kg, $D = \frac{10}{19} \cdot 29 = 15.26$ cm.

Solve the Problem DDD That a Spring Is Stretched by a Hanging Object Varies

Solve the Problem $D$ That a Spring Is Stretched by a Hanging Object Varies