Solve the problem.
-The volume $V$ of a gas varies inversely as the pressure $P$ on it. The volume of a gas is $300 \mathrm{~cm}^{3}$ under a pressure of $31 \mathrm{~kg} / \mathrm{cm}^{2}$. Find an equation of variation.
A) $\mathrm{V}=\frac{9300}{\mathrm{P}}$
B) $\mathrm{V}=\frac{\mathrm{P}}{9300}$
C) $\mathrm{V}=9300 \mathrm{P}$
D) $\mathrm{V}=\frac{1}{\mathrm{P}}$

Question

Quizplus · Accepted Answer

The volume $V$ of a gas varies inversely as the pressure $P$, which means $V = \frac{k}{P}$, where $k$ is a constant. Given $V = 300$ cm$^3$ and $P = 31$ kg/cm$^2$, we find $k = 300 \times 31 = 9300$. Thus, the equation of variation is $V = \frac{9300}{P}$.

Solve the Problem VVV Of a Gas Varies Inversely as the Pressure

Solve the Problem $V$ Of a Gas Varies Inversely as the Pressure