Solve the problem.
-A rectangular garden has dimensions of 23 feet by 13 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 352 square feet?
A) $6.5 \mathrm{ft}$
B) $6 \mathrm{ft}$
C) $4 \mathrm{ft}$
D) $5 \mathrm{ft}$

Question

Quizplus · Accepted Answer

The area of the garden is $23 \times 13 = 299$ square feet. The total area, including the path, is $299 + 352 = 651$ square feet. Let the width of the path be $x$. The dimensions of the garden plus the path are $(23 + 2x)$ by $(13 + 2x)$. The equation is $(23 + 2x)(13 + 2x) = 651$. Solving for $x$ gives $x = 4$ feet.

Solve the Problem 6.5ft6.5 \mathrm{ft}6.5ft B) 6ft6 \mathrm{ft}6ft C) 4ft4 \mathrm{ft}4ft D) 5ft5 \mathrm{ft}5ft

Solve the Problem $6.5 \mathrm{ft}$ B) $6 \mathrm{ft}$ C) $4 \mathrm{ft}$ D) $5 \mathrm{ft}$