Solve.
-A recipe calls for $\frac{2}{5} \mathrm{~L}$ of water and $\frac{3}{5} \mathrm{~L}$ of milk. If the recipe is halved, how much liquid will be needed?
A) $1 \mathrm{~L}$
B) $\frac{12}{5} \mathrm{~L}$
C) $\frac{1}{2} \mathrm{~L}$
D) $2 \mathrm{~L}$

Question

Quizplus · Accepted Answer

Halving the recipe means taking half of the total liquid needed ($\frac{2}{5} + \frac{3}{5} = 1 \mathrm{~L}$), so half of 1 L is $\frac{1}{2} \mathrm{~L}$.

Solve -A Recipe Calls For \frac{2}{5} 25 L\frac{2}{5} \mathrm{~L}52​ L Of Water And 35 L\frac{3}{5} \mathrm{~L}53​ L

Solve
-A Recipe Calls For \frac{2}{5} $\frac{2}{5} \mathrm{~L}$ Of Water And $\frac{3}{5} \mathrm{~L}$