Solve the problem. Use 3.14 for $\pi$.
-A rubber ice-hockey puck has a 3.3 in. diameter. What is the surface area of one flat side of the puck?
A) 8.54865 in. 2
B) 34.1946 in. 2
C) 10.362 in. 2
D) 4.27433 in. ${ }^{2}$

Question

Quizplus · Accepted Answer

The surface area of one flat side of the puck is $\pi r^2$, where r is the radius of the puck. The radius is half the diameter, so r = 3.3 in. / 2 = 1.65 in. Therefore, the surface area of one flat side of the puck is $\pi (1.65 in.)^2$ = 8.54865 in. 2.

Solve the Problem π\piπ -A Rubber Ice-Hockey Puck Has a 3

Solve the Problem $\pi$
-A Rubber Ice-Hockey Puck Has a 3