Solve.
-Susan's back yard is rectangular with dimensions 44 yd. by 76 yd. Carlos's back yard is rectangular with dimensions $25 \mathrm{yd}$. by $48 \mathrm{yd}$. How much larger is the area of Susan's back yard than the area of Carlos's back yard?
A) $2144 \mathrm{yd}^{2}$
B) $4544 \mathrm{yd}^{2}$
C) 94 yd. $^{2}$
D) $3344 \mathrm{yd}^{2}$

Question

Quizplus · Accepted Answer

The area of Susan's back yard is $44 \times 76 = 3344 \mathrm{yd}^{2}$. The area of Carlos's back yard is $25 \times 48 = 1200 \mathrm{yd}^{2}$. The difference in area is $3344 - 1200 = 2144 \mathrm{yd}^{2}$.

Solve -Susan's Back Yard Is Rectangular with Dimensions 44 Yd 25yd25 \mathrm{yd}25yd

Solve
-Susan's Back Yard Is Rectangular with Dimensions 44 Yd $25 \mathrm{yd}$