Solve.
-If an object is dropped off a cliff, after 7 seconds it will have fallen $\frac{32 \cdot 7^{2}}{2}$ feet, ignoring air resistance. Express this distance in standard form, without exponents.
A) $1568 \mathrm{ft}$
B) $65 \mathrm{ft}$
C) $784 \mathrm{ft}$
D) $39 \mathrm{ft}$

Question

Quizplus · Accepted Answer

The formula given is a simplification of the equation for distance fallen under gravity, which is $d = \frac{1}{2}gt^2$ where $g$ is the acceleration due to gravity (32 ft/s$^2$ in this case) and $t$ is the time in seconds. Plugging in 7 seconds for $t$, we get $\frac{32 \cdot 7^2}{2} = \frac{32 \cdot 49}{2} = 16 \cdot 49 = 784$ feet.

Solve -If an Object Is Dropped Off a Cliff, After 32⋅722\frac{32 \cdot 7^{2}}{2}232⋅72​

Solve
-If an Object Is Dropped Off a Cliff, After $\frac{32 \cdot 7^{2}}{2}$