Write an equation for the word problem. Then solve and check.
-During a sale, the price of a jacket was reduced by $\frac{1}{3}$. With a coupon, an additional $\$ 10$ was taken off at the cash register. If the final price of the jacket was $\$ 50$, what was the original price?
A) $x-\frac{1}{3}=50-10 ; \$ 60.00$
B) $\frac{1}{3} x-10=50 ; \$ 180$
C) $x-\frac{1}{3} x-10=50 ; \$ 90$
D) $x-\frac{1}{3} x=50 ; \$ 75.00$

Question

Quizplus · Accepted Answer

The correct equation to represent the situation is $x - \frac{1}{3}x - 10 = 50$, where $x$ is the original price of the jacket. Solving this equation gives the original price as \$90.

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