Solve the problem.
-A change in the weather can affect the movement of the glacial ice. Recently, the ice was recorded as moving $13 \mathrm{mcsec}$ faster than in a previous recording. Express in seconds the change in time.
A) $0.00013 \mathrm{sec}$
B) $0.000013 \mathrm{sec}$
C) $0.0000013 \mathrm{sec}$
D) $0.0013 \mathrm{sec}$

Question

Quizplus · Accepted Answer

The change in time is given in microseconds ($\mathrm{mcsec}$), which is $13 \mathrm{mcsec}$. To convert microseconds to seconds, divide by $1,000,000$. Thus, $13 \mathrm{mcsec} = 13 \times 10^{-6} \mathrm{sec} = 0.000013 \mathrm{sec}$.

Solve the Problem 13mcsec13 \mathrm{mcsec}13mcsec Faster Than in a Previous Recording 0.00013sec0.00013 \mathrm{sec}0.00013sec

Solve the Problem $13 \mathrm{mcsec}$ Faster Than in a Previous Recording $0.00013 \mathrm{sec}$