A ball is dropped from a height of 43 feet. On each bounce, it bounces to $77 \%$ of its previous height. How high does it get after the 5th bounce? (Round to the nearest hundredth, if necessary.)
A) 11.64 feet
B) 136.35 feet
C) 186.96 feet
D) 15.12 feet

Question

Quizplus · Accepted Answer

The height after each bounce can be calculated using the formula for the nth term of a geometric sequence, $h_n = h_0 \times r^{(n-1)}$, where $h_0$ is the initial height, $r$ is the common ratio (in this case, 0.77), and $n$ is the bounce number. After the 5th bounce, the height is $43 \times 0.77^4 \approx 11.64$ feet.

A Ball Is Dropped from a Height of 43 Feet 77%77 \%77%

A Ball Is Dropped from a Height of 43 Feet $77 \%$