Suppose $ r_{1}=10\left(\cos \frac{\pi}{8}+i \sin \frac{\pi}{8}\right) $ and $ r_{2}=5\left(\cos \frac{\pi}{15}+i \sin \frac{\pi}{15}\right) $ . Find the polar form of $ r_{1} r_{2} $ . Give the exact answer using radians for $ \theta $ .

Question

Suppose  $ r_{1}=10\left(\cos \frac{\pi}{8}+i \sin \frac{\pi}{8}\right) $  and $ r_{2}=5\left(\cos \frac{\pi}{15}+i \sin \frac{\pi}{15}\right) $  . Find the polar form of $ r_{1} r_{2} $  . Give the exact answer using radians for $ \theta $  .

Quizplus · Accepted Answer

The Answer of Suppose  $ r_{1}=10\left(\cos \frac{\pi}{8}+i \sin \frac{\pi}{8}\right) $  and $ r_{2}=5\left(\cos \frac{\pi}{15}+i \sin \frac{\pi}{15}\right) $  . Find the polar form of $ r_{1} r_{2} $  . Give the exact answer using radians for $ \theta $  .

Suppose r1=10(cos⁡π8+isin⁡π8) r_{1}=10\left(\cos \frac{\pi}{8}+i \sin \frac{\pi}{8}\right) r1​=10(cos8π​+isin8π​) And r2=5(cos⁡π15+isin⁡π15) r_{2}=5\left(\cos \frac{\pi}{15}+i \sin \frac{\pi}{15}\right) r2​=5(cos15π​+isin15π​)

Suppose $r_{1}=10\left(\cos \frac{\pi}{8}+i \sin \frac{\pi}{8}\right)$ And $r_{2}=5\left(\cos \frac{\pi}{15}+i \sin \frac{\pi}{15}\right)$