Given that $ \sin \left(22.5^{\circ}\right)=\frac{\sqrt{2-\sqrt{2}}}{2} $ , find an exact expression for $ \tan 22.5^{\circ} $ :

Name: Given that $ \sin \left(22.5^{\circ}\right)=\frac{\sqrt{2-\sqrt{2}}}{2} $ , find an exact expression for $ \tan 22.5^{\circ} $ :
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Question

Given that  $ \sin \left(22.5^{\circ}\right)=\frac{\sqrt{2-\sqrt{2}}}{2} $  , find an exact expression for  $ \tan 22.5^{\circ} $ :

Quizplus · Accepted Answer

The Answer of Given that  $ \sin \left(22.5^{\circ}\right)=\frac{\sqrt{2-\sqrt{2}}}{2} $  , find an exact expression for  $ \tan 22.5^{\circ} $ :

Given That sin⁡(22.5∘)=2−22 \sin \left(22.5^{\circ}\right)=\frac{\sqrt{2-\sqrt{2}}}{2} sin(22.5∘)=22−2​​​ , Find an Exact Expression For

Given That $\sin \left(22.5^{\circ}\right)=\frac{\sqrt{2-\sqrt{2}}}{2}$ , Find an Exact Expression For