Find the smallest positive number x such that $ \sin \left(x^{2}-18 x+80\right)=0 $ And $ -\pi

Name: Find the smallest positive number x such that $ \sin \left(x^{2}-18 x+80\right)=0 $ And $ -\pi< x^{2}-18 x+80<\pi $ .
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Question

Find the smallest positive number x such that  $ \sin \left(x^{2}-18 x+80\right)=0 $ And  $ -\pi< x^{2}-18 x+80<\pi $  .

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The Answer of Find the smallest positive number x such that  $ \sin \left(x^{2}-18 x+80\right)=0 $ And  $ -\pi< x^{2}-18 x+80<\pi $  .

Find the Smallest Positive Number X Such That sin⁡(x2−18x+80)=0 \sin \left(x^{2}-18 x+80\right)=0 sin(x2−18x+80)=0

Find the Smallest Positive Number X Such That $\sin \left(x^{2}-18 x+80\right)=0$