Find a constant c such that $ f\left(10^{100}\right) \approx 4 $ , where $ f(x)=\frac{x^{3}-20 x^{2}+12 x-16}{4 x^{3}-8 x^{2}+x-3} $ .

Name: Find a constant c such that $ f\left(10^{100}\right) \approx 4 $ , where $ f(x)=\frac{x^{3}-20 x^{2}+12 x-16}{4 x^{3}-8 x^{2}+x-3} $ .
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The Answer of Find a constant c such that $ f\left(10^{100}\right) \approx 4 $ , where $ f(x)=\frac{x^{3}-20 x^{2}+12 x-16}{4 x^{3}-8 x^{2}+x-3} $ .

Find a Constant C Such That f(10100)≈4 f\left(10^{100}\right) \approx 4 f(10100)≈4

Find a Constant C Such That $f\left(10^{100}\right) \approx 4$