An industrial plant consisting primarily of induction motor loads absorbs $1000 \mathrm{~kW}$ at 0.7 power factor lagging. (a) Compute the required kVA rating of a shunt capacitor to improve the power factor to 0.9 lagging. (b) Calculate the resulting power factor if a synchronous motor rated $1000 \mathrm{hp}$ with $90 \%$ efficiency operating at rated load and at unity power factor is added to the plant instead of the capacitor. Assume constant voltage. $(1 \mathrm{hp}=0.746 \mathrm{~kW})$

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The Answer of An industrial plant consisting primarily of induction motor loads absorbs $1000 \mathrm{~kW}$ at 0.7 power factor lagging. (a) Compute the required kVA rating of a shunt capacitor to improve the power factor to 0.9 lagging. (b) Calculate the resulting power factor if a synchronous motor rated $1000 \mathrm{hp}$ with $90 \%$ efficiency operating at rated load and at unity power factor is added to the plant instead of the capacitor. Assume constant voltage. $(1 \mathrm{hp}=0.746 \mathrm{~kW})$

An Industrial Plant Consisting Primarily of Induction Motor Loads Absorbs 1000 kW1000 \mathrm{~kW}1000 kW

An Industrial Plant Consisting Primarily of Induction Motor Loads Absorbs $1000 \mathrm{~kW}$