Repeat Example 7.1 with $\mathrm{V}=4 \mathrm{kV}, \mathrm{X}=3 \Omega$, and $\mathrm{R}=1 \Omega$.

Name: Repeat Example 7.1 with $\mathrm{V}=4 \mathrm{kV}, \mathrm{X}=3 \Omega$, and $\mathrm{R}=1 \Omega$.
Brand: Quizplus
Rating: 4.9 (40 reviews)

Question

Quizplus · Accepted Answer

The Answer is (a)

\bar{Ƶ}=1+j 3=3.1623 \angle 71.57^{\circ} \Omega

I_{a c}=\frac{V}{Ƶ}=\frac{4000}{3.1623}=\underline{\underline{1265 . \mathrm{A}}}

(b)

I_{r m s}(0)=1265 \sqrt{3}=\underline{2191.A }

(c)

\frac{X}{R}=3 \quad k(5)=\sqrt{1+2 e^{-4 \pi(5) / 3}}=1.0

I_{r m s}(5)=k(5) I_{a c}=1.0(1265)=1265 . \mathrm{A}

(d)

\alpha=\sin ^{-1}\left(\frac{300}{4000 \sqrt{2}} ight)=3.04^{\circ}

\begin{aligned}T & =\frac{L}{R}=\frac{X}{W R}=\frac{3}{(2 \pi 60)(1)}=7.958 imes 10^{-3} \mathrm{~S} \i_{d c}(t) & =\frac{-\sqrt{2}(4000)}{3.1623} \sin \left(3.04^{\circ}-71.57^{\circ} ight) e^{-t / T} \i_{d c}(t) & =\underline{\underline{1665 . e^{-t /\left(7.958 imes 10^{-3} ight)}} \mathrm{A}}\end{aligned}

Repeat Example 7 V=4kV,X=3Ω\mathrm{V}=4 \mathrm{kV}, \mathrm{X}=3 \OmegaV=4kV,X=3Ω , And R=1Ω\mathrm{R}=1 \OmegaR=1Ω

Repeat Example 7 $\mathrm{V}=4 \mathrm{kV}, \mathrm{X}=3 \Omega$ , And $\mathrm{R}=1 \Omega$